t^2-2t+6=5

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Solution for t^2-2t+6=5 equation: 



t^2-2t+6=5

We move all terms to the left:

t^2-2t+6-(5)=0

We add all the numbers together, and all the variables

t^2-2t+1=0

a = 1; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·1·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{2}{2}=1$

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